Question 5.
No: of experimental outcomes of 1 =3
No: of experimental outcomes of 2 =6
Total no: of Experimental observations=
3+6+1+5+3+2=20 outcomes.
No: of favourable experimental outcomes(outcomes of 1 + outcomes of 2) =3+6= 9 outcomes.
Therefore; Required probability=9/20 =0.45
Question 2
From The figure:The sphere is divided into 8 equal parts of which the letter "R" occupies 4 spaces.
So; Total no: of outcomes =8
No: of Favourable outcomes =4
Required Probability = 4/8 =1/2 =0.5
Hope it helps...
Regards;
Leukonov/Olegion.
