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Jimmy is trying to dive down and touch the bottom of the pool. On his first try he makes it 1/3 of the way to the bottom. On his second try he makes it 3/5 of the way to the bottom. Jimmys second dive was deeper than his first dive by what fraction of the pool?

Respuesta :

Louli

Answer:

Jimmy's second dive was [tex]\frac{4}{15}[/tex] of the pool deeper than the first one

Explanation:

We are given that:

First dive was [tex]\frac{1}{3}[/tex] of the way to the bottom

Second dive was [tex]\frac{3}{5}[/tex] of the way to the bottom

We know that the second dive was deeper than the first one since [tex]\frac{3}{5} > \frac{1}{3}[/tex]

To know how much deeper the second dive was compared to the first one, we will simply subtract the depth of the first dive from that of the second one

Therefore:

The second dive was [tex]\frac{3}{5} - \frac{1}{3} = \frac{9}{15} - \frac{5}{15} = \frac{4}{15}[/tex] of the pool deeper than the first one

Hope this helps :)

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