[tex]\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=&\stackrel{bases}{parallel}\\ &sides\\ h=&height\\ \cline{1-2} a=&2\\ b=&6\\ A=&24 \end{cases}\implies 24=\cfrac{h(2+6)}{2}\implies 24=\cfrac{h(8)}{2} \\\\\\ 24=4h\implies \cfrac{24}{4}=h\implies 6=h[/tex]
