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Given: m HL =40°, m EV =130°, m VL =110°. Find: m∠EYH.

Please answer fast Will give brainliest Given m HL 40 m EV 130 m VL 110 Find mEYH class=

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Answer:

The measure of angle EYH is [tex]25\°[/tex]

Step-by-step explanation:

step 1

Find the measure of arc EH

we know that

[tex]arc\ EV+arc\ VL+arc\ HL+arc\ EH=360\°[/tex] ----> by complete circle

substitute the given values

[tex]130\°+110\°+40\°+arc\ EH=360\°[/tex]

[tex]280\°+arc\ EH=360\°[/tex]

[tex]arc\ EH=360\°-280\°=80\°[/tex]

step 2

Find the measure of angle EYH

we know that

The measurement of the outer angle is the semi-difference of the arcs which comprises

[tex]m<EYH=\frac{1}{2}(arc\ EV-arc\ EH)[/tex]

substitute the values

[tex]m<EYH=\frac{1}{2}(130\°-80\°)=25\°[/tex]

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