Answer: 2.61
Step-by-step explanation:
Given data (x) : 7,5,10,11,12
Mean of the data : [tex]\overline{x}=9[/tex]
Number of data values : n= 5
Now, [tex]\sum (x-\overline{x})^2=(7-9)^2+(5-9)^2+(10-9)^2+(11-9)^2+(12-9)^2[/tex]
i.e. [tex]\sum (x-\overline{x})^2=34[/tex]
Now, the standard deviation for this data is given by :-
[tex]\sigma=\sqrt{\dfrac{\sum (x-\overline{x})^2}{n}}\\\\\sigma=\sqrt{\dfrac{34}{5}}=2.60768096208\approx2.61[/tex]
