Answer:
[tex]1.84\cdot 10^5 J[/tex]
Explanation:
The heat absorbed by the piece of iron is given by:
[tex]Q=mC_S \Delta T[/tex]
where:
m = 34 g is the mass of the piece of iron
[tex]C_s = 450 J/g^{\circ}C[/tex] is the specific heat of iron
[tex]\Delta T=24 C-12 C=12^{\circ}C[/tex] is the variation of temperature of the piece of iron
Substituting numbers into the formula, we find
[tex]Q=(34 g)(450 J/gC)(12 C)=1.84\cdot 10^5 J[/tex]
