Answer:
Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄
Explanation:
The correct formulas are
Al₄C₃ + H₂O ⟶ Al(OH)₃ + CH₄
Often, the best way to start is to balance all atoms other than O and H, then balance O, then balance H.
1. Put a 1 in front of the most complicated-looking formula (Al₄C₃):
1Al₄C₃ + H₂O ⟶ Al(OH)₃ + CH₄
2. Balance Al:
We have fixed 4 Al on the left. We need 4 Al on the right. Put a 4 in front of Al(OH)₃.
1Al₄C₃ + H₂O ⟶ 4Al(OH)₃ + CH₄
3. Balance C:
We have fixed 3 C on the left. We need 3 C on the right. Put a 3 in front of CH₄.
1Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄
4. Balance O:
We have fixed 12 O on the right. We need 12 O on the left. Put a 12 in front of H₂O.
1Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄
Every formula now has a fixed coefficient. The equation should be balanced.
5. Check that atoms balance:
\[tex]\begin{array}{ccc}\textbf{Atom} & \textbf{On the left} & \textbf{On the right}\\\text{Al} & 4 & 4\\\text{C} & 3 & 4\\\text{H} & 24 & 24\\\text{O} & 12 & 12\\\end{array}[/tex]
The balanced equation is
Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄
Answer:Al4C + 4(H20) = 4AL(OH) +CH4
Explanation:
the equation is balance on both sides,
4 aluminums on both sides
1 carbon on both sides
8 hydrogens on both sides
4 oxygens on both sides
