find the equation of the line passing through the point (3,1) and (7,-7)
Y=-2/5x -1 is the answer I believe, if anything check Photomath, that should be the right slope double check the y-intercept by plugging it in with your points provided to u
Answer:y = -2x + 7
Step-by-step explanation:
The equation of a straight line when two points are given is y - y1 = m(x - x1) but m is gradient which is y2 - y1 / x2 - x1
Substitute the points (3 ,1 ) and (7 , -7)
To the gradient equation and solve for the gradient which is m = -2 .Now with the gradient and the first point (3 , 1) solve for the equation
:• y - 1 = -2(x -3 )
y - 1 = -2x +6
. y = -2x + 7