Find the perimeter of the polygon defined by the coordinates (5, 8), (12, 0), (-5, 0), and (-12, 8). (Round to nearest tenth)
A)53.2
B)55.3
C)56.3
D)57.3
[tex]\displaystyle\\\text{We have the points:}\\E(5,~8)\\F(12,~0)\\G(-5,~0)\\H(-12,~8)\\\\EF=\sqrt{(5-12)^2+(8-0)^2}=\sqrt{(-7)^2+8^2}=\\=\sqrt{49+64}=\sqrt{113}\approx\boxed{\bf10.63}\\\\FG=12-(-5)=12+5=\boxed{\bf17}\\\\GH=\sqrt{(-5-(-12))^2+(0-8)^2}=\sqrt{7^2+(-8)^2}=\\=\sqrt{49+64}=\sqrt{113}\approx\boxed{\bf10.63}\\\\HE=|-12-5|=|-17|=\boxed{\bf17}\\\\P=EF+FG+GH+HE=10.63+17+10.63+17=55.26\approx\boxed{\bf55.3}\\\\\text{Correct answer: }~B)[/tex]
