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[tex]\displaystyle\\{\bf Method 1:}\\\\d=\sqrt{(3-3)^2+(6-1)^2}=\sqrt{0^2+5^2}=\sqrt{25}=\boxed{\bf5}\\\\{\bf Method 2:}\\\\\text{The points are the same vertical as they have the same abscissa.}\\\\\implies~~d=6-1=\boxed{\bf5}[/tex]

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