Consider a right cone with radius 2 and height 6. Its volume is V = π(2)26, or 8π units3.

If the height is changed to 3, does this have the same effect on the volume as changing the radius to 1?

If the height is now 3, then the new volume is π units3.

If the radius is now 1, then the new volume is π units3.

Therefore, changing the height to half of its original value and changing the radius to half of its original value does the volume. Halving the height of the cone the volume, while halving the radius of the cone results in the volume.

If the height is now 3, then the new volume is 4[tex]\pi[/tex] units[tex]^{3}[/tex]. If the radius is now 1, then the new volume is 2[tex]\pi[/tex] units[tex]^{3}[/tex]. Therefore, changing the height to half of its original value and changing the radius to half of its original value does not have the same effect on the volume. Halving the height of the cone halves the volume, while halving the radius of the cone results in 1/4 the volume.

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jainveenamrata jainveenamrata · Answer 2 · 2022-05-21T11:18:05+02:00

If the height is changed to 3, then the same effect will not be there on the volume as changing the radius to 1.

What is Geometry?

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

Consider a right cone with radius 2 and height 6. Its volume is V = (1/3)π(2)²6, or 8π units³.

If the height is changed to 3, this has the same effect on the volume as changing the radius to 1 will be

Then the volume of the cylinder in both cases.

If height is changed to 3. Then we have

Volume = (1/3)π(2)²3

Volume = 4π

If the radius is changed to 1. Then we have

Volume = (1/3)π(3)²6

Volume = 18π

More about the geometry link is given below.

https://brainly.com/question/7558603

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