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The revenue, in dollars, of a company that makes toy cars can be modeled by the polynomial 3x2 + 4x – 60. The cost, in dollars, of producing the toy cars can be modeled by 3x2 – x + 200. The number of toy cars sold is represented by x. If the profit is the difference between the revenue and the cost, what expression represents the profit?

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carlosego

Answer: [tex]profit=5x-260[/tex]

Step-by-step explanation:

To solve this exercise you must subtract the polynomials given in the problem.

Therefore, if:

[tex]revenue=3x^2+4x-60\\cost=3x^2-x+200[/tex]

Then, the profit is the shown below:

[tex]profit=revenue-cost\\profit=3x^2+4x-60-(3x^2-x+200)\\profit=3x^2+4x-60-3x^2+x-200[/tex]

Add the like terms.

Therefore, you obtain:

[tex]profit=5x-260[/tex]

Answer:

[tex]5x-260[/tex]      

Step-by-step explanation:

Given :

The revenue, in dollars, of a company that makes toy cars can be modeled by the polynomial [tex]3x^2 + 4x -60[/tex]

The cost, in dollars, of producing the toy cars can be modeled by [tex]3x^2 -x + 200.[/tex]

To Find: Profit function

Solution:

Revenue = [tex]3x^2 + 4x -60[/tex]

Cost = tex]3x^2 -x + 200[/tex]

Now we are supposed to find the profit

So, Profit = Revenue - Cost

[tex]Profit=3x^2 + 4x -60-(3x^2 -x + 200)[/tex]      

[tex]Profit=3x^2 + 4x -60-3x^2 +x - 200[/tex]      

[tex]Profit=5x-260[/tex]      

Hence The expression represents the profit is [tex]5x-260[/tex]      

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