Respuesta :

Answer: third option

Step-by-step explanation:

To solve the problem you must apply the proccedure shown below:

- Descompose the numerator and the denominator of the given fraction into its prime numbers:

[tex]64=2*2*2*2*2*2\\144=2*2*2*2*3*3[/tex]

Then you can rewrite:

[tex]64=2^6\\144=2^4*3^2[/tex]

Then:

[tex]\±\sqrt{\frac{{2^6}}{{2^4*3^2}}}=\±\frac{2^3}{2^2*3}=\±\frac{8}{4*3}=\±\frac{8}{12}[/tex]

Therefore, the answer is: [tex]-\frac{8}{12}\ and\ \frac{8}{12}[/tex]

Answer:

The correct answer is option 3

-8/12 and 8/12

Step-by-step explanation:

It is given that square roots of 64/144

The given number is a fraction.

The numerator of  the square root and denominator both are perfect squares. So it is easy to find the square root of given number

To find the square root of 64/144

we have , √64 = ±8 and 144 = ±12

√(64/144) = ± 8/12

Therefore, √(64/144) = 8/12 or √(64/144) = -8/12

Therefore the correct answer is option 3

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