Answer:
[tex]\large\boxed{d.\ 11.3\ cm}[/tex]
Step-by-step explanation:
Look at the picture.
CQ is a perpendicular bisector of PR. Therefore QR = QP.
[tex]PR=16\ cm\to QP = 16 cm : 2 = 8\ cm[/tex]
The segment CP is a radius of the given circle.
We have the right triangle CQP. Use the Pythagorean theorem:
[tex]CQ^2+QP^2=CP^2[/tex]
Substitute CQ = 8 cm and QP = 8 cm.
[tex]CP^2=8^2+8^2\\\\CP^2=64+64\\\\CP^2=128\to CP=\sqrt{128}\\\\CP\approx11.3\ cm[/tex]
