What is the specific latent heat of fusion of ice if it takes 863 kJ to convert 4.6 kg of ice into water at 0 C?​

Respuesta :

Answer:

[tex]1^{f} =187.7 \frac{J}{kg}[/tex]

Explanation:

SO in order to calculate the specific latent heat of fusion, you need to remember the formula:

[tex]1^{f} =\frac{Q}{m}[/tex]

Where [tex]1^{f}[/tex] representes the specific latent heart of fusion.

[tex]Q[/tex] represents the heat energy added, usually represented in kJ

[tex]m[/tex] represents the mass of the object, in kg.

Now that we have our formula we just have to put our values into the formula:

[tex]1^{f} =\frac{Q}{m}[/tex]

[tex]1^{f} =\frac{863kJ}{4.6kg}[/tex]

[tex]1^{f} =187.7 \frac{J}{kg}[/tex]

SO our answer would be [tex]1^{f} =187.7 \frac{J}{kg}[/tex]

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