Answer:
11x - y = -79
Step-by-step explanation:
The standard form of an equation of a line:
[tex]Ax+By=C[/tex]
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point
We have the points (-7, 2) and (-8, -9). Substitute:
[tex]m=\dfrac{-9-2}{-8-(-7)}=\dfrac{-11}{-1}=11[/tex]
[tex]y-2=11(x-(-7))\\\\y-2=11(x+7)[/tex]
Convert to the standard form:
[tex]y-2=11(x+7)[/tex] use the distributive property a(b + c) = ab + ac
[tex]y-2=11x+77[/tex] add 2 to both sides
[tex]y=11x+79[/tex] subtract 11x from both sides
[tex]-11x+y=79[/tex] change the signs
[tex]11x-y=-79[/tex]
