Answer:
[tex]sin = \frac{\sqrt{5} }{3}[/tex]
Step-by-step explanation:
SOH CAH TOA
Where:
s = sin
c = cos
t = tan
o = opposite
a = adjacent
h = hypotenuse
cos = 2/3 where 2 is adjacent side and 3 is hypotenuse, now find opposite side using a^2 + b^2 = c^2 //c is hypotenuse side
2^2 + b^2 = 3^2
4 + b^2 = 9
b^2 = 9 - 4
b^2 = 5
b = square root (5) = 5^(1/2) //opposite side
sin = O/H
[tex]sin = \frac{\sqrt{5} }{3}[/tex]
//Hope it helps.
