Answer:
[tex]\large\boxed{y=a(x+8)(x+1)(x-3)}[/tex]
Step-by-step explanation:
[tex]\text{Factored form:}\\\\y=a(x-x_1)(x-x_2)(x-x_3)\\\\x_1,\ x_2,\ x_3-zeros\\\\\text{We have}\ x_1=-8,\ x_2=-1\ \text{and}\ x_3=3.\ \text{Substitute:}\\\\y=a(x-(-8))(x-(-1))(x-3)\\\\y=a(x+8)(x+1)(x-3)\\\\\text{Where}\ a\neq0\ (\text{any real number except 0})[/tex]
