Answer:
The volume of the model is [tex]321\ m^{3}[/tex]
Step-by-step explanation:
we know that
The volume of the sphere (model of the earth) is equal to
[tex]V=\frac{4}{3}\pi r^{3}[/tex]
In this problem we have
[tex]r=8.5/2=4.25\ m[/tex] ----> the radius is half the diameter
substitute the values
[tex]V=\frac{4}{3}(3.14)(4.25)^{3}=321\ m^{3}[/tex]
