Answer: [tex]35\sqrt{x^2y}[/tex]
Step-by-step explanation:
To solve this exercise you must apply the proccedure shown below:
- Apply multiplication, as following:
[tex]4(5\sqrt{x^2y})+3(5\sqrt{x^2y})=20\sqrt{x^2y}+15\sqrt{x^2y}[/tex]
- As you can see, the index of the radical in the first term is 2 and the index of the radical in the second term is also 2.
- You can observe that the radicands are the same.
- Therefoe, as the index of the first radical is equal to the index of the second radical and the radicands are the same, you can make the addition. Then, you obtain:
[tex]35\sqrt{x^2y}[/tex]
