Answer:
The surface area is [tex]2,440\ m^{2}[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The surface area of a triangular prism is equal to
[tex]SA=2B+PH[/tex]
where
B is the area of the triangular base
P is the perimeter of the triangular face
H is the height of the prism
Find the area of the base B
[tex]B=\frac{1}{2}(42)(20)=420\ m^{2}[/tex]
Find the perimeter of the base P
[tex]P=(42+29+29)=100\ m[/tex]
we have
[tex]H=16\ m[/tex]
substitute the values
The surface area is
[tex]SA=2(420)+100(16)=2,440\ m^{2}[/tex]
