Answer:
√50
√65
√145
105 °
Step-by-step explanation:
Given the coordinates
A(-3, 6)
B(2, 1)
C(9, 5)
To find the length of AB ,AC and BC, we will use distance formula
√((x2-x1)² + (y2-y1)²)
AB:
√(2+3)² + (1-6)²
√5²+5²
√50
BC:
√(9-2)² + (5-1)²
√7² + 4²
√49+16
√65
AC:
√(9+3)² + (5-6)²
√12²+1²
√145
To find ∠ABC
cos(B) = c² + a² − b² / 2ca
= 65 + 50 - 145 / 2(√65)(√50)
cosB = -0.26311
B = cos^-1(-0.26311)
= 105 °
