Suppose a computer technical support representative can answer calls from 8 customers in an hour. What is the probability that a customer will be on hold less than 15 minutes?
Answer:
Option d
Step-by-step explanation:
We need 2 fundamental data to solve this problem.
1.- Average number of clients attended in 1 hour.
2.- Time in which it is expected that a client will be attended.
They tell us that the average number of clients served in an hour is m = 8
They tell us to calculate the probability that the client will be seen in less than 15 minutes.
But the time t in the formula is given in hours.
Therefore we must write 15 minutes according to hours.
We know that [tex]1\ hour = 60 minutes[/tex].
So:
[tex]15\ minutes[\frac{1\ hour}{60\ minutes}] = 0.25\ hours[/tex].
Now we substitute in the formula [tex]m = 8[/tex] and [tex]t = 0.25[/tex] to find P.
[tex]P = 1 -e^{-mt}\\\\P = 1- e^{-(8)(0.25)}\\\\P = 1 - e^{-2}\\\\P = 0.8646\\\\P= 86\%[/tex]