Answer:
Step-by-step explanation:
Think of '2' as being on the positive x-axis and that -2i being on the negative y-axis. The resultant of these two vectors has magnitude √(2²+[-2]²), which comes out to 2√2.
Since the resultant of these two vectors lies in Quadrant IV, we measure the angle from the positive x-axis counterclockwise into Quadrant IV. The positive angle associated with this is 315°; the negative one is -45°
We are now in a position to express 2 - 2i in trig form:
2√2 angle 315°
that is, the magnitude of this resultant vector is 2√2 and the vector, located in QIV, has the angle 315° as measured from the positive x-axis.
