Answer:
5.1 days
Step-by-step explanation:
Given in the question,
initial amount of substance = 34 grams
k-value = 0.137
To find the half life of this substance we will use following formula
[tex]N(0)/2 = N(0)e^{-kt}[/tex]
here N(0) is initial amount of substance
t is time in days
Plug values in the formula
[tex]34 /2 = 34e^{-0.137t}[/tex]
1/2 = e^{-0.137t}
Take logarithm on both sides
ln(1/2) = ln( e^{-0.137t})
ln(1/2) = -0.137t
t = ln(1/2) / -0.137
t = 5.059
t ≈ 5.1 days (nearest to tenths)
