Respuesta :
Answer:
Step-by-step explanation:
The general equation for a circle of radius r with center at (h, k) is
(x - h)² + (y - k)² = r²
Here, this equation becomes:
(x - 1)² + (y - 2)² = 3²
Equation of the circle way to represent the circle in the coordinate plane using its center points and the radius. The equation of the circle centered at the point (1,2) and has a radius of length 3 can be given as,
[tex]x^2+y^2-2x-4y-4=0[/tex]
Given-
The center point of the given circle is (1,2).
The length of the radius of the circle is 3 units.
What is the equation of the circle?
Equation of the circle way to represent the circle in the coordinate plane using its center points and the radius.
The standard form of the equation of the circle is,
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Here,
(h,k) is the center of the circle.
[tex]r[/tex] is the radius of the circle.
Put the values given in the problem in the standard form of the equation of the circle. Thus,
[tex](x-1)^2+(y-2)^2=3^2[/tex]
[tex]x^2+1-2x+y^2+4-4y=9[/tex]
[tex]x^2+y^2-2x-4y+5-9=0[/tex]
[tex]x^2+y^2-2x-4y-4=0[/tex]
Thus the equation of the circle centered at the point (1,2) and has a radius of length 3 can be given as,
[tex]x^2+y^2-2x-4y-4=0[/tex]
Learn more about the equation of the circle here;
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