Answer:
The solutions are {-5, 1}
Step-by-step explanation:
Next time, please use the symbol " ^ " to denote exponentiation:
x^2+4x-5=0
Start by identifying the coefficient of the x term (it is 4 here). Divide this by 2, resulting in 2. Square this result (square 2), obtaining 4.
Now add this 4 after the 4x term, and then subtract this 4:
x^2+4x +4 - 4 -5=0
Rewrite x^2+4x + 4 as (x + 2)²:
(x + 2)² - 9 = 0
Add 9 to both sides, to isolate (x + 2):
(x + 2)² = 9
Take the square root of both sides:
x + 2 = ±3
Solve for x: x = -2 + 3, or 1
x = -2 - 3, or -5
The solutions are {-5, 1}
