Answer:
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-3, -1) and (-6, 8). Substitute:
[tex]m=\dfrac{8-(-1)}{-6-(-3)}=\dfrac{9}{-3}=-3\\\\y-8=-3(x-(-6))\\\\y-8=-3(x+6)[/tex]