Answer:
Explanation:
We are given that an equation
[tex]Ca(OH)_2+H_3PO_4\rightarrow Ca_3(PO_4)2+H_2O[/tex]
We have to find the proper way to balance the equation
Calculate number of  atoms each type of element on left hand side and on right side
On left hand side
Number of atoms of Ca=1
Number of oxygen atoms=6
Number of phosphorous atom=1
Number of hydrogen atoms=5
On right hand side
Number of  Ca atoms=3
Number of oxygen atoms=9
Number of phosphorous atom=2
Number of hydrogen atoms=2
We substitute 3 as stoichiometric coefficient of [tex]Ca(OH)_2[/tex] and 2 as stoichiometric coefficient of [tex]H_3PO_4[/tex]
Then, the equation
[tex]3Ca(OH)_2+2H_3PO_4\rightarrow Ca_3(PO_4)_2+H_2O[/tex]
Now,Number of oxygen on left side =14
Number of hydrogen atom on left side =12
Therefore, we substituting 6 as stoichiometric coefficient of water
Then ,we get
[tex]3Ca(OH)_2+2H_3PO_4\rightarrow Ca_3(PO_4)_2+6H_2O[/tex]
Now, we have on left side
Total number of oxygen atom=14
Total number of hydrogen atom=12
Total number of phosphorous atom=2
Total number of Ca atom=3
On right side
Total number of oxygen atom=14
Number of hydrogen atom=12
Number of phosphorous atom=2
Number of Ca atom=3
Hence, the equation is balance.
Answer:
Lars is balancing equations with his study group. He is unsure about one equation because each member of the study group came up with a different answer. Which is the proper way to balance the equation Ca(OH)2 + H3PO4 → Ca3(PO4)2 + H2O?
the correct answer is the 2nd option
3Ca(OH)2 + 2H3PO4 → Ca3(PO4)2 + 6H2O
Explanation:
i did the quiz and got it right
