Answer:
The answer in the procedure
Step-by-step explanation:
we know that
The formula to calculate the slope between two points is equal to
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
step 1
Find the slope between (-3, -2) and (1, 0)
[tex]m=\frac{0+2}{1+3}[/tex]
[tex]m=\frac{2}{4}=\frac{1}{2}[/tex]
Find the equation of the line
[tex]y-y1=m(x-x1)[/tex]
with m and the point (1,0)
substitute
[tex]y-0=\frac{1}{2}(x-1)[/tex]
[tex]y=\frac{1}{2}x-\frac{1}{2}[/tex]
step 2
Find the slope between (-2, -1) and (4, 2)
[tex]m=\frac{2+1}{4+2}[/tex]
[tex]m=\frac{3}{6}=\frac{1}{2}[/tex]
Find the equation of the line
[tex]y-y1=m(x-x1)[/tex]
with m and the point (4,2)
substitute
[tex]y-2=\frac{1}{2}(x-4)[/tex]
[tex]y=\frac{1}{2}x-2+2[/tex]
[tex]y=\frac{1}{2}x[/tex]
Compare the equation of the two lines
The two lines are parallel, because their slope is the same, but are different lines
therefore
Beatrice's conclusion is incorrect
All of these points are not on the same line, because are different parallel lines
The slope between (-2,-1) and (1,0) is equal to [tex]\frac{1}{2}[/tex]
Answer:
Beatrice is incorrect. All of these points are not on the same line because the slope between (-2, -1) and (1, 0), which are coordinates from each of the pairs above, is not equivalent equal to 1/2
Step-by-step explanation:
