WORTH 99 POINTS PLEASE ANSWER!!! The table shows the solubility of two substances in water at 20 °C. Solubility of Substances Mass (kg) Solubility of Sodium Chloride (g per 100 g of water) Solubility of Lead Nitrate (g per 100 g of water) 100 L K 200 36 54 Part 1: What will be the values of L and K for 100 kg of each substance? Part 2: Explain your answer for Part 1.

If the solubility for L in 200kg of water is 36g then to find the solubility in 100kg of water, you would divided 36 by 2 to find half. You would do the same to find K, if in 200kg of water K's solubility is 54, you would divided 54 by 2 to get 27.

Explanation:

also you only set this question to 5 points not 99, if this helps at all could you mark me brainliest? :) have a great day!