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For which of the following is the arc between the two hands of a clock greater than a semicircle?
The long arm is at 12 and the short arm is in-between the 12 and the 1

A The hands are at 11 and 6; arc measured clockwise


B The hands are at 11 and 6; arc measured counterclockwise


C The hands are at 2 and 8; arc measured counterclockwise


D The hands are at 2 and 8; arc measured clockwise

Respuesta :

chikafujiwara

Answer:

A

Step-by-step explanation:

Each hour is 30 degrees. 11 to 6 is 7 hours so 30 * 7 = 210 degrees, which is greater than a semicircle, which is 180 degrees.

david8644

Answer:

A. The hands are at 11 and 6; arc measured clockwise

Step-by-step explanation:

A semicircle measures 180º and when you measure the distance from 11 to 6 the difference in the hands of the clock by each hour is given by the equation:

[tex]\frac{360}{12}[/tex]= 30

So there are 7 numbers between the 11 and the 6 if you measure it clockwise, that means that the angle formed by the two hands of the clock measured clockwise is:

7*30= 210

Wich is greater than 180º, which is why that is the correct answer.

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