Respuesta :

Answer:

The system has no real solutions

Step-by-step explanation:

we have

[tex]y=-3x-1[/tex] ----> equation A

[tex]y=x^{2}-3x+4[/tex] ----> equation B

we know that

The solution of the system of equations is the intersection points both graphs

using a graphing tool

Graphics do not intersect

see the attached figure

therefore

The system has no real solutions

Ver imagen calculista

There is no real solution to the two systems of equation.

What is a System of the equation?

Inconsistent System

A system of equations to have no real solution, the lines of the equations must be parallel to each other.

Consistent System

1. Dependent Consistent System

A system of the equation to be Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.

2. Independent Consistent System

A system of the equation to be Independent Consistent System the system must have one unique solution for which the lines of the equation must intersect at a particular.

As two equations that are given to us are y=−3x−1 and y=x²−3x+4. Now, the solution of the equation is the points at which the two functions intersect.

Plotting the two graphs on the graph, we will notice that the two points are not intersecting at any point.

Hence, there is no real solution to the two systems of equation.

Learn more about System of the equation:

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