Respuesta :
Answer:
Step-by-step explanation:
The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is
[tex]x=\sqrt{(-y-10)(y+2)} +5,-\sqrt{(-y-10)(y+2)} +5[/tex]
Steps:
(x-5)²+(y+6)²=4²
Rewrite:
(x-5)²+(y-(-6))²=4²
Answer:
Step-by-step explanation:
The center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2 is
[tex]x=\sqrt{(-y-10)(y+2)} +5,-\sqrt{(-y-10)(y+2)} +5[/tex]
Steps:
(x-5)²+(y+6)²=4²
Rewrite:
(x-5)²+(y-(-6))²=4²