Respuesta :
The equation of a circle:
[tex](x-a)^2+(y-b)^=r^2[/tex]
(a, b) - center of the circle
r - radius
We have:
[tex](x+2)^2+(y-5)^2=25\\\\(x-(-2))^2+(y-5)^2=5^2\\\\(-2,\ 5)\to center\\5\to radius[/tex]
The equation of a circle:
[tex](x-a)^2+(y-b)^=r^2[/tex]
(a, b) - center of the circle
r - radius
We have:
[tex](x+2)^2+(y-5)^2=25\\\\(x-(-2))^2+(y-5)^2=5^2\\\\(-2,\ 5)\to center\\5\to radius[/tex]