Answer: [tex]\bold{C)\ -\dfrac{1}{2}}[/tex]
Step-by-step explanation:
[tex].\qquad \dfrac{x+2}{15}=\dfrac{x+1}{5}\\\\\\\rightarrow (15)\dfrac{x+2}{15}=\dfrac{x+1}{5}(15)\\\\\\\rightarrow x+2=3(x+1)\\\\\rightarrow x+2=3x+3\\\\\rightarrow \qquad 2=2x+3\\\\\rightarrow \qquad -1=2x\\\\\rightarrow \qquad -\dfrac{1}{2}=x[/tex]
