Answer: [tex]\bold{B)\ \dfrac{x-2}{x+1}}[/tex]
Step-by-step explanation:
Factor the numerator (top of fraction) and denominator (bottom of fraction). Then cancel out the common factor.
To factor, find two numbers whose product is the c-value and sum is the b-value.
x² + 5x - 14
∧
-1 +14 = 13
-2 +7 = 5 this works!
So, x² + 5x - 14 = (x - 2)(x + 7)
x² + 8x + 7
∧
1 +7 = 8 this work!
So, x² + 8x + 7 = (x + 1)(x + 7)
[tex]\dfrac{x^2+5x-14}{x^2+8x+7}=\dfrac{(x+7)(x-2)}{(x+7)(x+1)}=\dfrac{x-2}{x+1}[/tex]
