By using the expression for the distance between two points J and K will be 13 units.
Distance between two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by the expression,
Distance = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Points given in the question,
Therefore, distance between these points will be,
JK = [tex]\sqrt{(4+4)^2+(4+6)^2}[/tex]
JK = [tex]\sqrt{64+100}[/tex]
= [tex]\sqrt{164}[/tex]
= 12.80
≈ 13 units
Therefore, distance between the given points J and K is 13 units.
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