The answer is: C2H6
First, we need to find the empirical formula of the compound:
Looking for the relative atomic mass for each element:
[tex]C=12.011g/mol\\H=1.008g/mol[/tex]
Finding the number of moles for each element:
[tex]C=32g*\frac{1mole}{12.011g}=2.67mole\\H=8g*\frac{1mole}{1.008g}=7.93mole[/tex]
Then, we need to determinate the mole ratio by dividing each result into the smallest number:
[tex]C=\frac{2.67}{2.67}=1\\\\H=\frac{7.93}{2.67}=2.97=3[/tex]
So, the empirical formula would be CH3
We are given the molar mass of the compound is equal to 30 g/mol
We need to compare the empirical formula molecular mass and the molecular formula molar mass in order to find the number of atoms of the compound:
Empirical formula molar mass:
[tex]CH3=12.011+(1.008)*3=15.03g/mol[/tex]
Molecular formula molar mass = 30.0 g/mol
So, by dividing the molecular formula molar mass by the empirical formula molar mass we have the number of atoms of the compound:
[tex]\frac{30g/mol}{15.03g/mol}=2[/tex]
Therefore,
The molecular formula will be: (CH3)2= C2H6
Have a nice day!
