Answer:
The products in the following double displacement reaction is [tex]CaCO_{3}+2NaCl[/tex]
Explanation:
Ina double displacement reaction, cations and anions of two ionic species exchange their partners, forming new compounds.
Here ([tex]Ca^{2+}and Cl^{-}[/tex]) and ([tex]Na^{+}and CO_{3}^{2-}[/tex]) are two different ionic pairs. Reaction between these two pairs resulting exchange of ionic species between them. Hence [tex]CaCO_{3}and NaCl[/tex] are formed as products of the given reaction.
[tex]CaCl_{2}+Na_{2}CO_{3}\rightarrow CaCO_{3}+2NaCl[/tex]
