Solve the absolute value inequality: |x + 12| + 5 < 27 Isolate the absolute value by subtracting 5 from both sides. Sepárate into a compound inequality

Respuesta :

Answer:

The solution of the compound inequality is

(-34,∞)∩ (-∞,10)=(-34,10)

Step-by-step explanation:

we have

[tex]\left|x+12\right|+5<27[/tex]

Subtract 5 both sides

[tex]\left|x+12\right|<27-5[/tex]

[tex]\left|x+12\right|<22[/tex]

Separate into a compound inequality

[tex]x+12 <22[/tex] ------> inequality A

[tex]-(x+12)<22[/tex] ------> inequality B

Solve inequality A

[tex]x+12 <22[/tex]

[tex]x <22-12[/tex]

[tex]x <10[/tex]

The solution is the interval (-∞,10)

Solve inequality B

[tex]-(x+12)<22[/tex]

Multiply by -1 both sides

[tex](x+12)>-22[/tex]

[tex]x>-22-12[/tex]

[tex]x>-34[/tex]

The solution is the interval (-34,∞)

therefore

The solution of the compound inequality is

(-34,∞)∩ (-∞,10)=(-34,10)

Answer:

(-34,∞)∩ (-∞,10)=(-34,10)

Step-by-step explanation:

its the seaperate compound inequality

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