Answer:
[tex]\cos ^{-1}(\frac{6.3}{9.8})[/tex]
[tex]\sin^{-1} (\frac{7.5}{9.8})[/tex]
Step-by-step explanation:
Recall and use the mnemonics SOH to obtain;
[tex]\sin(\angle ABC) =\frac{Opposite}{Hypotenuse}[/tex]
This implies that;
[tex]\sin(m \angle ABC) =\frac{7.5}{9.8}[/tex]
Take the inverse sine of both sides to get;
[tex]m\angle ABC =\sin^{-1} (\frac{7.5}{9.8})[/tex]
Also,
[tex]\cos (m\angle ABC)=\frac{Adjacent}{Hypotenuse}[/tex]
[tex]\cos (m\angle ABC)=\frac{6.3}{9.8}[/tex]
[tex]\Rightarrow m\angle ABC=\cos ^{-1}(\frac{6.3}{9.8})[/tex]
