Complex number in standard form
Answer:
B. (13/3 - 3i)
Step-by-step explanation:
Given: (3i - 2/3) - (6i - 5)
Here we have to subtract.
To simplify we have to combine real numbers and complex number(i.e) terms with "i"
= 3i - 2/3 -6i + 5 [distributed the negative sign inside the parenthesis]
= -2/3 + 5 + 3i - 6i[Combine real numbers and complex numbers]
= 13/3 - 3i
Therefore, the answer is B. (13/3 - 3i)
Hope this will helpful.
Thank you.
Answer:
Choice B is the answer.
Step-by-step explanation:
We have given an expression.
[tex](3i-\frac{2}{3})-(6i-5)[/tex]
We have to simplify it and write it as complex number in standard form.
a+bi is a complex number in standard form.
[tex]3i-\frac{2}{3}-6i+5[/tex]
Adding like terms, we have
[tex](-\frac{2}{3}+5)+(3-6)i[/tex]
[tex](\frac{-2+15}{3})+(-3)i[/tex]
[tex](\frac{13}{3})+(-3)i[/tex]
[tex]\frac{13}{3}-3i[/tex] which is standard form of complex number.