The value of the function when t=5 is 15.32
Initial amount f(0) =12
Rate of growth dy/dt = 0.59([tex]1.05^t[/tex])
Given function is:
[tex]y = 12(1.05)^t[/tex]
A function is a rule which defines a relationship between independent variable x and dependent variable f(x).
So, function value at t = 5 will be:
f(5) = [tex]12(1.05)^5[/tex]
f(5) = 15.32
For initial amount put t=0 in function
f(0) = [tex]12(1.05)^0 =12[/tex]
Rate of growth dy/dt = d/dt ([tex]12(1.05)^t[/tex]) = [tex]12ln(1.05) 1.05^t[/tex] =0.59([tex]1.05^t[/tex])
Therefore, the value of the function when t=5 is 15.32
Initial amount f(0) =12
Rate of growth dy/dt = 0.59([tex]1.05^t[/tex])
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