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Answer:

see explanation

Step-by-step explanation:

given

a² + b² = c² ( isolate b² by subtracting a² from both sides )

b² = c² - a² ( take the square root of both sides )

[tex]\sqrt{b^{2} }[/tex] = ± [tex]\sqrt{c^2-a^2}[/tex]

b = ± [tex]\sqrt{c^2-a^2}[/tex]

From the given Pythagorean theorem, a² + b² = c², the solution for b is [tex]b = \pm\sqrt{c^{2} - a^{2}}[/tex]

The correct option is the second one [tex]b = \pm\sqrt{c^{2} - a^{2}}[/tex]

From the question,

The Pythagorean theorem is given as a² + b² = c²

To solve for b, we will make b the subject of the formula

  • First, subtract a² from both sides, we get

[tex]a^{2} - a^{2} + b^{2} = c^{2} - a^{2}[/tex]

Then,

[tex]b^{2} = c^{2} - a^{2}[/tex]

  • Now, take the square root of both sides, we get

[tex]\sqrt{b^{2}} = \pm\sqrt{c^{2} - a^{2}}[/tex]

Then,

[tex]b = \pm\sqrt{c^{2} - a^{2}}[/tex]

Hence, from the given Pythagorean theorem, a² + b² = c², the solution for b is [tex]b = \pm\sqrt{c^{2} - a^{2}}[/tex]

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