The Pythagorean theorem is a^2+b^2=c^2
Solve for b.
Answer:
see explanation
Step-by-step explanation:
given
a² + b² = c² ( isolate b² by subtracting a² from both sides )
b² = c² - a² ( take the square root of both sides )
[tex]\sqrt{b^{2} }[/tex] = ± [tex]\sqrt{c^2-a^2}[/tex]
b = ± [tex]\sqrt{c^2-a^2}[/tex]
From the given Pythagorean theorem, a² + b² = c², the solution for b is [tex]b = \pm\sqrt{c^{2} - a^{2}}[/tex]
The correct option is the second one [tex]b = \pm\sqrt{c^{2} - a^{2}}[/tex]
From the question,
The Pythagorean theorem is given as a² + b² = c²
To solve for b, we will make b the subject of the formula
[tex]a^{2} - a^{2} + b^{2} = c^{2} - a^{2}[/tex]
Then,
[tex]b^{2} = c^{2} - a^{2}[/tex]
[tex]\sqrt{b^{2}} = \pm\sqrt{c^{2} - a^{2}}[/tex]
Then,
[tex]b = \pm\sqrt{c^{2} - a^{2}}[/tex]
Hence, from the given Pythagorean theorem, a² + b² = c², the solution for b is [tex]b = \pm\sqrt{c^{2} - a^{2}}[/tex]
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