Answer:
A
Step-by-step explanation:
Note that
[tex]\csc x=\dfrac{1}{\sin x}[/tex]
and
[tex]\cot x=\dfrac{\cos x}{\sin x}.[/tex]
Then
[tex]\dfrac{\csc x}{\cot x}=\dfrac{\frac{1}{\sin x}}{\frac{\cos x}{\sin x}}=\dfrac{1}{\cos x}=\sec x.[/tex]
Since [tex]\dfrac{\csc x}{\cot x}=\sqrt{2},[/tex] you have that [tex]\sec x=\sqrt{2}.[/tex]
