Find the area of a triangle with a =4, b =6, and c =8.
Answer:
D
Step-by-step explanation:
The area of the triangle can be calculated using formula
[tex]A=\sqrt{p(p-a)(p-b)(p-c)},[/tex]
where p is half of the perimeter.
1. If a=4, b=6 and c=8, then
[tex]p=\dfrac{a+b+c}{2}=\dfrac{4+6+8}{2}=9\ un.[/tex]
2. The area is
[tex]A=\sqrt{9\cdot (9-4)(9-6)(9-8)}=\sqrt{9\cdot 5\cdot 3\cdot 1}=3\sqrt{15}\approx 11.6\ un^2.[/tex]
Answer:
Choice D is correct.
Step-by-step explanation:
We have given the sides of triangle:
a =4, b=6, and c =8.
We have to find the area of a triangle.
The formula for the area of triangle is given by:
[tex]A=\sqrt{p(p-a)(p-b)(p-c)}[/tex]
We have to find the valye of p:
[tex]p=\frac{a+b+c}{2}[/tex]
[tex]p=\frac{4+6+8}{2}[/tex]
p= 9 units
[tex]A= \sqrt{9(9-4)(9-6)(9-8)}[/tex]
[tex]A= \sqrt{9.5.3.1} =3\sqrt{15}[/tex]
A ≈ 11 .6 units² is the area of triangle.