What basic trigonometric identity would you use to verify that sin x con x tan x= 1-cos^2x?
Answer:
The answer is (a) ⇒ tanx = sinx/cosx
Step-by-step explanation:
∵ (sinx)(cosx)(tanx) = (sinx)(cosx)(sinx/cosx) = sin²x
∵ sin²x = 1-cos²x
∴ L.H.S = R.H.S
∴ (sinx)(cosx)(tanx) = 1 - cos²x