Answer: d) s ≤ -18
Step-by-step explanation:
[tex]\text{negative s over 3 }\bigg(-\dfrac{s}{3}\bigg)\quad \text{is greater than or equal to 6 }\bigg(\geq6\bigg)\\ \\\rightarrow \quad -\dfrac{s}{3}\geq6\\\\\\\text{multiply both sides by -3 (remember to flip the inequality symbol):}\\\\-\dfrac{s}{3}(-3)\geq6(-3)\qquad \rightarrow \qquad s\leq-18[/tex]
