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Find the area of parallelogram ABCD given m A = 30 and the following measures. AB = 6 ft.; AX = 3√3 A = ? A. 18 ft.² B. 18√3 ft.² C. 36√3 ft.²

Find the area of parallelogram ABCD given m A 30 and the following measures AB 6 ft AX 33 A A 18 ft B 183 ft C 363 ft class=

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Answer:

Given that a parallelogram ABCD has sides AB= 6 ft and AX = 3√3

Angle A =30

To find the area of the parallelogram

We have area of parallelogram = base x height

Here base can be taken as side AB = 6 ft

Height = perpendicular distance of AB from vertex X

= AX sin A

= 3√3sin30

=1.5√3

Hence area =6(1.5√3)=9√3ft^2

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Step-by-step explanation:

Answer:

18√3 ft²

Step-by-step explanation:

The area of a parallelogram is given by the formula

A = bh, where b is the length of the base and h is the length of the height.

The base of the parallelogram is AB, which is 6 ft.

The height forms a right angle with the base; this is AX, which is 3√3.

This makes the area 6(3√3) = 18√3 ft²

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